[2539]Python 判断变量是否是一个方法
[蚁方阵《Python判断对象是否是function的三种方法》](https://blog.csdn.net/yiifaa/article/details/78046331)
(https://stackoverflow.com/questions/624926)
最后选择 callable
# callable
> If this is for Python 2.x or for Python 3.2+, you can also use callable(). It used to be deprecated, but is now undeprecated, so you can use it again. You can read the discussion here: http://bugs.python.org/issue10518. You can do this with:
callable(obj)
# hasattr
If this is for Python 3.x but before 3.2, check if the object has a __call__ attribute. You can do this with:
hasattr(obj, '__call__')
# FunctionTypes
The oft-suggested types.FunctionTypes approach is not correct because it fails to cover many cases that you would presumably want it to pass, like with builtins:
>>> isinstance(open, types.FunctionType)
False
>>> callable(open)
True
# isfunction
>>> from inspect import isfunction
>>> def f(): pass
>>> isfunction(f)
True
>>> isfunction(lambda x: x)
True
页:
[1]